JEE Main Chemistry question
At a given temperature the Kc for PCl₅(g) ⇌ PCl₃(g) + Cl₂(g) is 2.4×10⁻³. At the same temperature, the Kc for PCl₃(g) + Cl₂(g) ⇌ PCl₅(g) is:
Answer: (C)
Solution
Kc(reverse) = 1/2.4×10⁻³ = 4.2×10².
At a given temperature the Kc for PCl₅(g) ⇌ PCl₃(g) + Cl₂(g) is 2.4×10⁻³. At the same temperature, the Kc for PCl₃(g) + Cl₂(g) ⇌ PCl₅(g) is:
Kc(reverse) = 1/2.4×10⁻³ = 4.2×10².