JEE Main Chemistry question
Kp₁, Kp₂ for X ⇌ Y+Z (1) and A ⇌ 2B (2) are in ratio 9:1. If degree of dissociation of X and A are equal, total pressure at equilibrium (1) and (2) are in ratio:
Answer: (B)
Solution
Kp₁ = P₁α²/(1−α²); Kp₂ = 4P₂α²/(1−α²). Kp₁/Kp₂ = P₁/(4P₂) = 9 → P₁/P₂ = 36.