JEE Main Chemistry question
A quantity of PCl₅ was heated in a 10 litre vessel at 250°C to form PCl₅(g) ⇌ PCl₃(g) + Cl₂(g). At equilibrium, the vessel contains 0.1 mole of PCl₅, 0.20 mole of PCl₃ and 0.20 mole of Cl₂. The equilibrium constant is:
Answer: (C)
Solution
Kc = (0.02)(0.02)/(0.01) = 0.04.