JEE Main Chemistry question
28 g N₂ and 6 g H₂ were mixed. At equilibrium 17 g NH₃ was formed. The weight of N₂ and H₂ at equilibrium are respectively:
Answer: (C)
Solution
1 mol NH₃ formed needs 0.5 mol N₂ (14 g) and 1.5 mol H₂ (3 g) consumed. Remaining: N₂ = 28−14 = 14 g; H₂ = 6−3 = 3 g.