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JEE Main Chemistry question

ChemistryChemical KineticsJEE Main

For a reaction N₂ + 3H₂ → 2NH₃; ΔH = −22 kcal. If energy of activation for this reaction is 70 kcal, the energy of activation for the backward reaction is:

Answer: (B)

Solution

Ea(back) = Ea(fwd) − ΔH = 70 − (−22) = 92 kcal.

Question ID VK-136033