JEE Main Chemistry question

The equilibrium constant for the reaction P₄(s) + 5O₂(g) ⇌ P₄O₁₀(s) is:

• (A)Kc = 1/[O₂]⁵Correct
• (B)Kc = [O₂]⁵
• (C)Kc = [P₄O₁₀]/(5[P₄][O₂])
• (D)Kc = [P₄O₁₀]/([P₄][O₂]⁵)