JEE Main Chemistry question
Amount of PCl₅ (in mole) needed to be added to a one litre vessel at 250°C in order to obtain a concentration of 0.1 mole of Cl₂ for the given change is: PCl₅⇌PCl₃+Cl₂; Kc=0.0414 mol/litre.
Answer: (A)
Solution
Kc=(0.1)(0.1)/(a−0.1)=0.0414 → a=0.3415.