JEE Main Chemistry question
The vapour density of completely dissociated NH₄Cl would be:
Answer: (B)
Solution
VD(observed)=VD(theoretical)/(1+α(n−1)); with α=1, n=2, VD becomes exactly half.
The vapour density of completely dissociated NH₄Cl would be:
VD(observed)=VD(theoretical)/(1+α(n−1)); with α=1, n=2, VD becomes exactly half.