JEE Main Chemistry question
A definite amount of solid NH₄HS is placed in a flask already containing NH₃ gas at a certain temperature and 0.50 atm pressure. NH₄HS decomposes to give NH₃ and H₂S and total pressure in the flask is 0.84 atm. The equilibrium constant for the reaction is:
Answer: (D)
Solution
Let x=rise in P(NH₃) from decomposition=P(H₂S). Total=0.50+2x=0.84→x=0.17. P(NH₃)=0.67,P(H₂S)=0.17. Kp=P(NH₃)×P(H₂S)=0.67×0.17≈0.11.