JEE Main Chemistry question
If 340 g of a mixture of N₂ and H₂ in the correct ratio gave a 20% yield of NH₃, the mass produced would be:
Answer: (D)
Solution
Stoichiometric mixture: 10 mol N₂ (280 g) + 30 mol H₂ (60 g) = 340 g. 20% of N₂ (2 mol) reacts → 4 mol NH₃ = 68 g.