JEE Main Chemistry question
In the equilibrium, 2SO₂(g)+O₂(g)⇌2SO₃(g), the partial pressure of SO₂, O₂ and SO₃ are 0.662, 0.101 and 0.331 atm respectively. What should be the partial pressure of oxygen so that the equilibrium concentrations of SO₂ and SO₃ are equal?
Answer: (A)
Solution
Kp=(0.331)²/[(0.662)²×0.101]=2.48. At new eq. with P(SO₂)=P(SO₃): Kp=1/P(O₂)' → P(O₂)'=1/2.48≈0.4 atm.