JEE Main Chemistry question
The dissociation equilibrium of a gas AB₂ can be represented as 2AB₂(g)⇌2AB(g)+B₂(g). The degree of dissociation is 'x' and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant Kp and total pressure p is:
Answer: (A)
Solution
From Kp=Px³/2 (Q1150/1211 pair), x=(2Kp/P)^(1/3).