JEE Main Chemistry question
The graph relates ln Keq vs 1/T for a reaction (graph shows a positive slope, i.e. ln Keq rises as 1/T increases). The reaction must be:
Answer: (A)
Solution
Since ln K = −ΔH/R×(1/T)+const, a positive slope (vs 1/T) means −ΔH/R>0, so ΔH<0 (exothermic).