JEE Main Chemistry question
The equilibrium constant for a reaction is 1×10²⁰ at 300 K. The standard Gibbs energy change for this reaction is:
Answer: (A)
Solution
ΔG°=−2.303RT logK=−2.303×8.314×300×20=−114.9 kJ≈−115 kJ.
The equilibrium constant for a reaction is 1×10²⁰ at 300 K. The standard Gibbs energy change for this reaction is:
ΔG°=−2.303RT logK=−2.303×8.314×300×20=−114.9 kJ≈−115 kJ.