JEE Main Chemistry question
The solubility of AgCl (Ksp=1.2×10⁻¹⁰) in a 0.10 M NaCl solution is:
Answer: (C)
Solution
[Ag⁺]=Ksp/[Cl⁻]=1.2×10⁻¹⁰/0.10=1.2×10⁻⁹ M.
The solubility of AgCl (Ksp=1.2×10⁻¹⁰) in a 0.10 M NaCl solution is:
[Ag⁺]=Ksp/[Cl⁻]=1.2×10⁻¹⁰/0.10=1.2×10⁻⁹ M.