JEE Main Chemistry question
If the dissociation constant of an acid HA is 1×10⁻⁵, the pH of a 0.1 M solution of the acid HA will be approximately:
Answer: (A)
Solution
[H⁺]=√(10⁻⁵×0.1)=10⁻³; pH=3.
If the dissociation constant of an acid HA is 1×10⁻⁵, the pH of a 0.1 M solution of the acid HA will be approximately:
[H⁺]=√(10⁻⁵×0.1)=10⁻³; pH=3.