JEE Main Chemistry question

Chemistry Equilibrium JEE Main

The dissociation constant of HCN is 1.3×10⁻⁹. The value of hydrolysis constant of KCN will be:

(A)1.3×10⁻⁹
(B)10⁻¹⁴
(C)7.7×10⁻⁵
(D)0.77×10⁻⁵Correct

Answer: (D)

Solution

Kh=Kw/Ka=10⁻¹⁴/1.3×10⁻⁹=7.7×10⁻⁶=0.77×10⁻⁵.

Question ID VK-136188