JEE Main Chemistry question
Ka for formic acid and acetic acid are 2.1×10⁻⁴ and 1.1×10⁻⁵ respectively. The relative strength of the acids is:
Answer: (D)
Solution
Relative strength (at equal C) ≈ √(Ka₁/Ka₂) = √(19.1) = 4.37.
Ka for formic acid and acetic acid are 2.1×10⁻⁴ and 1.1×10⁻⁵ respectively. The relative strength of the acids is:
Relative strength (at equal C) ≈ √(Ka₁/Ka₂) = √(19.1) = 4.37.