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JEE Main Chemistry question

ChemistryEquilibriumJEE Main

100 mL of 1 N NH₄OH (Kb=5×10⁻⁵) is neutralized to equivalence point by 1 N HCl. The pH of solution at equivalence point is:

Answer: (D)

Solution

NH₄Cl formed, [salt]=0.5M (diluted by equal volume). Ka(NH₄⁺)=Kw/Kb=2×10⁻¹⁰. [H⁺]=√(2×10⁻¹⁰×0.5)=10⁻⁵; pH=5.

Question ID VK-136223