JEE Main Chemistry question
The solubility product Ksp of a sparingly soluble salt AgIO₃ is 1.0×10⁻⁸ at a given temperature. What is the mass of AgIO₃ (molecular mass=283) contained in 100 mL of solution at this temperature?
Answer: (C)
Solution
s=√Ksp=1.0×10⁻⁴ M; in 100 mL: 1.0×10⁻⁵ mol × 283 = 2.83×10⁻³ g.