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JEE Main Chemistry question

ChemistryThermodynamicsJEE Main

Heat of neutralization for the reaction, NaOH+HCl→NaCl+H₂O, is 57.1 kJ mol⁻¹. What will be the heat released when 0.25 mole of NaOH is titrated against 0.25 mole of HCl?

Answer: (C)

Solution

Heat = 0.25 × 57.1 = 14.3 kJ.

Question ID VK-136232