JEE Main Chemistry question
The ionic product of water at 60°C is 9.61×10⁻¹⁴. The pH of water at 60°C is:
Answer: (A)
Solution
[H⁺]=√(9.61×10⁻¹⁴)=3.1×10⁻⁷; pH=6.51.
The ionic product of water at 60°C is 9.61×10⁻¹⁴. The pH of water at 60°C is:
[H⁺]=√(9.61×10⁻¹⁴)=3.1×10⁻⁷; pH=6.51.