JEE Main Chemistry question
The solubility of AgCl is 0.0015 g/litre. The solubility product of AgCl will be:
Answer: (B)
Solution
s=0.0015/143.5=1.05×10⁻⁵ M; Ksp=s²=1.1×10⁻¹⁰.
The solubility of AgCl is 0.0015 g/litre. The solubility product of AgCl will be:
s=0.0015/143.5=1.05×10⁻⁵ M; Ksp=s²=1.1×10⁻¹⁰.