JEE Main Chemistry question
0.1 M acetic acid solution is titrated against 0.1 M NaOH solution. What would be the difference in pH between 1/4 and 3/4 stages of neutralization of acid?
Answer: (D)
Solution
pH(3/4)−pH(1/4)=log(3)−log(1/3)=2log3.
0.1 M acetic acid solution is titrated against 0.1 M NaOH solution. What would be the difference in pH between 1/4 and 3/4 stages of neutralization of acid?
pH(3/4)−pH(1/4)=log(3)−log(1/3)=2log3.