JEE Main Chemistry question
50% neutralization of a solution of formic acid (Ka=2×10⁻⁴) with NaOH would result in a solution having a hydrogen ion concentration of:
Answer: (A)
Solution
At 50% neutralization [HA]=[A⁻], so [H⁺]=Ka=2×10⁻⁴.
50% neutralization of a solution of formic acid (Ka=2×10⁻⁴) with NaOH would result in a solution having a hydrogen ion concentration of:
At 50% neutralization [HA]=[A⁻], so [H⁺]=Ka=2×10⁻⁴.