JEE Main Chemistry question

Chemistry Equilibrium JEE Main

The solubility product of a salt AB₂ is 4×10⁻⁹ at 373 K. The solubility of AB₂ in boiling water will be:

(A)4×10⁻³ M
(B)4×10⁻⁴ M
(C)1×10⁻¹⁰ M
(D)1×10⁻³ MCorrect

Answer: (D)

Solution

4s³=4×10⁻⁹ → s³=10⁻⁹ → s=10⁻³ M.

Question ID VK-136328