JEE Main Chemistry question
If the concentration of CrO₄²⁻ ion in a saturated solution of silver chromate be 2×10⁻⁴ M, solubility product of silver chromate will be:
Answer: (C)
Solution
[Ag⁺]=2×(2×10⁻⁴)=4×10⁻⁴. Ksp=(4×10⁻⁴)²×2×10⁻⁴=32×10⁻¹².
If the concentration of CrO₄²⁻ ion in a saturated solution of silver chromate be 2×10⁻⁴ M, solubility product of silver chromate will be:
[Ag⁺]=2×(2×10⁻⁴)=4×10⁻⁴. Ksp=(4×10⁻⁴)²×2×10⁻⁴=32×10⁻¹².