JEE Main Chemistry question

Chemistry Equilibrium JEE Main

The concentration of fluoroacetic acid (Ka of acid=2.6×10⁻³) which is required to get [H⁺]=1.50×10⁻³ M is:

(A)0.865 M
(B)2.37×10⁻³ MCorrect
(C)2.37×10⁻⁴ M
(D)2.37×10⁻² M

Answer: (B)

Solution

Ka=[H⁺]²/(C−[H⁺]); solving gives C=1.5×10⁻³+8.65×10⁻⁴≈2.37×10⁻³ M.

Question ID VK-136337