JEE Main Chemistry question
Ksp of AgCl at 18°C is 1.8×10⁻¹⁰. If Ag⁺ of sodium is 4×10⁻³ mol/litre the Cl⁻ that must exceed before AgCl is precipitated would be:
Answer: (A)
Solution
[Cl⁻]=Ksp/[Ag⁺]=1.8×10⁻¹⁰/4×10⁻³=4.5×10⁻⁸ M.
Ksp of AgCl at 18°C is 1.8×10⁻¹⁰. If Ag⁺ of sodium is 4×10⁻³ mol/litre the Cl⁻ that must exceed before AgCl is precipitated would be:
[Cl⁻]=Ksp/[Ag⁺]=1.8×10⁻¹⁰/4×10⁻³=4.5×10⁻⁸ M.