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JEE Main Chemistry question

ChemistryEquilibriumJEE Main

Zn salt is mixed with (NH₄)₂S of molarity 0.021 M. The amount of Zn²⁺ remains unprecipitated in 12 mL of this solution (Ksp of ZnS=4.51×10⁻²⁴) is:

Answer: (A)

Solution

[Zn²⁺]=Ksp/[S²⁻]=4.51×10⁻²⁴/0.021=2.15×10⁻²² M; in 12 mL: 2.58×10⁻²⁴ mol × 65.4 g/mol ≈ 1.68×10⁻²² g.

Question ID VK-136397