JEE Main Chemistry question

Chemistry Equilibrium JEE Main

pH of a saturated solution of Ba(OH)₂ is 12. The value of solubility product (Ksp) of Ba(OH)₂ is:

(A)4.0×10⁻⁶
(B)5.0×10⁻⁶
(C)3.3×10⁻⁷
(D)5.0×10⁻⁷Correct

Answer: (D)

Solution

[OH⁻]=10⁻²; s=5×10⁻³; Ksp=4s³=5.0×10⁻⁷.

Question ID VK-136404