JEE Main Chemistry question
If the solubility of lithium sodium hexafluoroaluminate, Li₃Na₃(AlF₆)₂ is 'a' mol/litre, its solubility product is equal to:
Answer: (D)
Solution
Dissociation: 3Li⁺+3Na⁺+2AlF₆³⁻. Ksp=(3a)³(3a)³(2a)²=27a³×27a³×4a²=2916a⁸.