JEE Main Chemistry question

ChemistryEquilibriumJEE Main

If the solubility of lithium sodium hexafluoroaluminate, Li₃Na₃(AlF₆)₂ is 'a' mol/litre, its solubility product is equal to:

Answer: (D)

Solution

Dissociation: 3Li⁺+3Na⁺+2AlF₆³⁻. Ksp=(3a)³(3a)³(2a)²=27a³×27a³×4a²=2916a⁸.

Question ID VK-136425