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JEE Main Chemistry question

ChemistryEquilibriumJEE Main

At 25°C, the solubility product of Mg(OH)₂ is 1.0×10⁻¹¹. At which pH, will Mg²⁺ ions start precipitating in the form of Mg(OH)₂ from a solution of 0.001 M Mg²⁺ ions?

Answer: (C)

Solution

[OH⁻]=√(Ksp/[Mg²⁺])=√(10⁻⁸)=10⁻⁴; pOH=4; pH=10.

Question ID VK-136464