JEE Main Chemistry question
What is [H⁺] in mol/L of a solution that is 0.20 M in CH₃COONa and 0.1 M in CH₃COOH? Ka for CH₃COOH is 1.8×10⁻⁵.
Answer: (D)
Solution
[H⁺]=Ka×[acid]/[salt]=1.8×10⁻⁵×0.1/0.20=9.0×10⁻⁶.
What is [H⁺] in mol/L of a solution that is 0.20 M in CH₃COONa and 0.1 M in CH₃COOH? Ka for CH₃COOH is 1.8×10⁻⁵.
[H⁺]=Ka×[acid]/[salt]=1.8×10⁻⁵×0.1/0.20=9.0×10⁻⁶.