JEE Main Chemistry question
If pKb for CN⁻ at 25°C is 4.7, the pH of 0.5 M aqueous NaCN solution is:
Answer: (C)
Solution
pOH=½(pKb−logC)=½(4.7+0.301)=2.5; pH=14−2.5=11.5.
If pKb for CN⁻ at 25°C is 4.7, the pH of 0.5 M aqueous NaCN solution is:
pOH=½(pKb−logC)=½(4.7+0.301)=2.5; pH=14−2.5=11.5.