JEE Main Chemistry question
If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is:
Answer: (D)
Solution
[OH⁻]=10⁻²; s=5×10⁻³; Ksp=4s³=5.0×10⁻⁷.
If pH of a saturated solution of Ba(OH)₂ is 12, the value of its Ksp is:
[OH⁻]=10⁻²; s=5×10⁻³; Ksp=4s³=5.0×10⁻⁷.