JEE Main Chemistry question

Chemistry Equilibrium JEE Main

At 25°C, Kb for a base BOH is 1.0×10⁻¹². The [OH⁻] in 0.01 M aqueous solution of the base is:

(A)1.0×10⁻⁶ M
(B)1.0×10⁻⁷ MCorrect
(C)1.0×10⁻⁵ M
(D)2.0×10⁻⁶ M

Answer: (B)

Solution

[OH⁻]=√(10⁻¹²×0.01)=10⁻⁷ M.

Question ID VK-136521