JEE Main Chemistry question

Chemistry Equilibrium JEE Main

If 50 mL of 0.2 M KOH is added to 40 mL of 0.5 M HCOOH, the pH of the resulting solution is (Ka=1.8×10⁻⁴):

(A)3.75Correct
(B)5.6
(C)7.5
(D)3.4

Answer: (A)

Solution

mmol KOH=10 (limiting), mmol HCOOH=20. 10 mmol acid neutralized leaves

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Question ID VK-136532