JEE Main Chemistry question
Solution prepared by dissolving equal number of mole of HOCl (Ka=3.2×10⁻⁸) and NaOCl is a buffer of pH:
Answer: (C)
Solution
Equal moles → pH=pKa=−log(3.2×10⁻⁸)=7.5.
Solution prepared by dissolving equal number of mole of HOCl (Ka=3.2×10⁻⁸) and NaOCl is a buffer of pH:
Equal moles → pH=pKa=−log(3.2×10⁻⁸)=7.5.