JEE Main Chemistry question
In the hydrolytic equilibrium, A⁻+H₂O⇌HA+OH⁻, Ka=1.0×10⁻⁵. The degree of hydrolysis of 0.001 M solution of the salt is:
Answer: (A)
Solution
Kb(A⁻)=Kw/Ka=10⁻⁹; h=√(Kb/C)=√(10⁻⁹/0.001)=10⁻³.
In the hydrolytic equilibrium, A⁻+H₂O⇌HA+OH⁻, Ka=1.0×10⁻⁵. The degree of hydrolysis of 0.001 M solution of the salt is:
Kb(A⁻)=Kw/Ka=10⁻⁹; h=√(Kb/C)=√(10⁻⁹/0.001)=10⁻³.