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JEE Main Chemistry question

ChemistryEquilibriumJEE Main

Ksp of salts AB, AB₂ and A₃B are 4.0×10⁻⁸, 3.2×10⁻¹⁴ and 2.7×10⁻¹⁵ respectively at temperature T. The solubility order of these salts in water at temperature T (in mol litre⁻¹) is:

Answer: (D)

Solution

s(AB)=√(4×10⁻⁸)=2×10⁻⁴; s(AB₂)=(3.2×10⁻¹⁴/4)^(1/3)=2×10⁻⁵; s(A₃B)=(2.7×10⁻¹⁵/27)^(1/4)=10⁻⁴.

Question ID VK-136548