JEE Main Chemistry question
For the equilibrium, , the value of at 298 K is kJ mol⁻¹. (Take , )
Answer: 79.9
Solution
Δ G° = -RT = -8.314×298×
= -8.314×298×(-32.242) ≈ 79890\ J/mol
For the equilibrium, , the value of at 298 K is kJ mol⁻¹. (Take , )
Δ G° = -RT = -8.314×298×
= -8.314×298×(-32.242) ≈ 79890\ J/mol