JEE Main Chemistry question
10 mL of 0.2 M solution of requires 8 mL of 0.2 M acidified solution. The value of is .
Answer: 3
Solution
Moles of salt mmol; moles of mmol, i.e. meq of (n=5 in acid medium) meq of oxalate. Since each oxalate ion is 2
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account