JEE Main Chemistry question
Electrolysis of gives at anode. Vacuum distillation of gives HO. The number of peroxy (O–O) bonds present in and respectively are [EAMCET 2006]
Answer: (C)
Solution
Here is 50% HSO, which on electrolysis gives peroxydisulphuric acid, , at the anode; vacuum distillation of HSO then yields HO. HSO (X) has no O–O
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account