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JEE Main Chemistry question

ChemistryRedox ReactionsJEE Main

5.0 mL of HO solution liberates 1.016 g of I from an acidified KI solution. Thus, volume strength (at STP) is approximately…….

Answer: 9

Solution

, i.e. 1 mol HO ≡ 1 mol I. Moles of I$_2 =

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Question ID VK-137288