JEE Main Chemistry question
has 8.54% Mg, 48.75% Ba and remaining carbonate. 0.281 kg is decomposed by . formed is mole(s)
Answer: 2
Solution
Taking 100 g of the compound: mass of Mg g moles Mg ; mass of Ba g moles Ba ; remaining mass (carbonate) g moles . The mole ratio Mg:Ba:
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account