JEE Main Chemistry question
Calculate the amount of sodium carbonate (in grams) to be added to calcium chloride to prepare 50.0 g of calcium carbonate. [At. wt of C = 12, O = 16, Na = 23, Ca = 40, Cl = 35.5 u]
Answer: 53
Solution
The reaction is CaCl_2 + Na_2CO_3 \rightarrow CaCO_3 + 2NaCl, a 1:1 mole ratio between and . Moles of required \frac{50.0}{100}$ =
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