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JEE Main Chemistry question

ChemistryRedox ReactionsJEE Main

25.0 mL of 0.05 M solution of was boiled with excess of in acidic medium. The formed required 25.0 mL of 0.1 N in acidic medium. What is the oxidation number of the N in the new product?

Answer: 1

Solution

Moles of = mol. Equivalents of used = eq, which equals the moles of oxidised back to (since has n-factor 1), so formed mol. Since each

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Question ID VK-138448