JEE Main Chemistry question

Arrange the carbanions (CH₃)₃C⁻, C̄Cl₃, (CH₃)₂CH⁻, C₆H₅CH₂⁻ in order of their decreasing stability

(A)C₆H₅CH₂⁻ > C̄Cl₃ > (CH₃)₂CH⁻ > (CH₃)₃C⁻
(B)(CH₃)₂CH⁻ > C̄Cl₃ > C₆H₅CH₂⁻ > (CH₃)₃C⁻
(C)C̄Cl₃ > C₆H₅CH₂⁻ > (CH₃)₂CH⁻ > (CH₃)₃C⁻Correct
(D)(CH₃)₃C⁻ > (CH₃)₂CH⁻ > C₆H₅CH₂⁻ > C̄Cl₃

Answer: (C)

Solution

C̄Cl₃ is stabilized by the strong −I (electron-withdrawing) effect of three chlorines, which helps accommodate the negative charge, making it the most stable. C₆H₅CH₂⁻ is resonance-stabilized by the ring. Among the simple alkyl

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Question ID VK-139088