JEE Main Chemistry question

Which of the following requires a radical intermediate?

(A)CH₃–CH=CH₂ + HBr → CH₃–CH(Br)–CH₃
(B)CH₃–CHO + HCN → CH₃CH(OH)CN
(C)CH₃–CH=CH₂ + HBr --(peroxide)--> CH₃–CH₂–CH₂BrCorrect
(D)CH₃CHO + NH₂OH --(H⁺)--> CH₃–CH=N–OH

Answer: (C)

Solution

The anti-Markovnikov product (1-bromopropane) forming from propene and HBr is the hallmark of the peroxide-initiated free-radical chain addition mechanism; (A)

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Question ID VK-139092